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Understanding Mathematical Problem-Solving Through First Principles

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Chapter 1: Introduction to Triangular Triples

This content revolves around the Oxford University entrance exam question that exemplifies the systematic reasoning based on first principles, a method often utilized by proficient mathematicians and one that AI systems like GPT-4 find challenging.

Pythagorean theorem and triangular triples illustration

Most individuals are acquainted with the properties of right-angled triangles. According to the Pythagorean Theorem, for two shorter sides denoted as a and b, and the longest side c, the equation a² + b² = c² holds true. The integer solutions to this theorem are known as Pythagorean Triples, with classic examples being (3, 4, 5) and (5, 12, 13).

A broader concept is that of Triangular Triples. This term refers to any group of three positive integers that can represent the lengths of a triangle's sides. While integer Pythagorean triples are indeed triangular triples, the definition extends further: a set of integers (a, b, c) qualifies as a triangular triple if, when arranged in non-decreasing order, the sum of the two smaller integers exceeds the largest one.

For instance, consider the set (4, 2, 3). This can form a triangle since 2 + 3 > 4. Likewise, (2, 2, 2) is a triangular triple; however, (1, 3, 1) fails this criterion as it cannot form a triangle (1 + 1 ≤ 3).

A recent Oxford University problem addressed triangular triples and serves as an excellent illustration of how to deconstruct complex problems into manageable parts using first principles.

The problem introduces a function f(P) for P > 2, defined as the number of triangular triples summing to P. Specifically, it asks us to determine f(21). Though calculating the number of triangular triples summing to 21 may seem daunting, a systematic approach reveals a simple solution. Additionally, I will demonstrate that AI, such as GPT-4, often struggles with questions requiring this foundational reasoning.

Here are the problem's components and my solutions, which I found both intriguing and a valuable exercise in mathematical reasoning requiring minimal textbook knowledge.

Section 1.1: Initial Calculations

  1. Calculate f(3), f(4), f(5), and f(6).

This part familiarizes us with the concept. The only positive integer triple that sums to three is (1, 1, 1), which is a triangular triple, thus f(3) = 1. For a sum of 4, the integers must include 2, but since (1, 1, 2) does not satisfy the triangular condition, f(4) = 0. Analyzing the sum of 5, the integers must involve either 2 or 3. The configurations (2, 2, 1), (2, 1, 2), and (1, 2, 2) qualify as triangular triples, leading to f(5) = 3. Lastly, for f(6), the only valid triangular triple is (2, 2, 2), giving f(6) = 1.

The first video, "Differentiation from First Principles - HOW TO GET THE MARKS IN YOUR A-LEVEL EXAM," elaborates on the foundational techniques essential for mastering differentiation.

Section 1.2: Proving Properties of Triangular Triples

  1. For any triangular triple (a, b, c), demonstrate that (a+1, b+1, c+1) is also a triangular triple.

Assuming a, b, c are in non-decreasing order, we can derive that (a+1) + (b+1) = (a+b) + 2 > c + 2 > c + 1. Hence, (a+1, b+1, c+1) forms a triangular triple.

  1. If (x, y, z) is a triangular triple and x+y+z is even and at least 6, show that x, y, z are all at least 2, and that (x-1, y-1, z-1) is also a triangular triple.

Assuming x, y, z are arranged in increasing order, we need to prove that x cannot equal 1. If x = 1, then y+z must be odd, contradicting the initial condition of evenness. Thus, x must be greater than 1.

Section 1.3: Establishing Relationships Between f(P)

  1. For any positive integer k ≥ 3, show that f(2k-3) = f(2k).

By the previous proof, we know that each triangular triple summing to 2k-3 can be uniquely mapped to one summing to 2k by adding 1 to each number, meaning the counts of both sets must equal.

  1. Let S ≥ 3 and P = 2S. Show that (a, b, c) is a triangular triple summing to P if and only if each of a, b, c is strictly less than S.

We will prove this in both directions, establishing that if a+b > c, then c must be less than S, and vice versa.

  1. For any a with 2 ≤ a ≤ S-1, show that the number of valid b values such that (a, b, P-a-b) is a triangular triple is a-1.

Based on the previous findings, we can conclude that for a specific value of a, b can take values ranging from S-a+1 to S-1, yielding a total of a-1 possible values.

  1. Derive an expression for f(P) for any even P that is at least 6.

Let (a, b, P-a-b) be a triangular triple. Since a can range from 2 to S-1, and for each a, there are a-1 valid b's, we can formulate f(P) based on these parameters.

Graphical representation of triangular triples
  1. Calculate f(21).

Using the result from (iv), we find that f(21) = f(24). Since 24 is an even number greater than 6, we apply our established formula, with S set to 12, yielding a total of 55.

To validate this, I also created a simple counting function in R:

n_triangular_triples <- function(P) {

check <- c()

for (a in 1:P) {

for (b in 1:(P - a)) {

if (P - a - b > 0) {

sorted <- sort(c(a, b, P - a - b))

if ((sum(sorted) == P) && (sorted[1] + sorted[2] > sorted[3])) {

check <- append(check, 1)

}

}

}

}

sum(check)

}

By running this function for P = 21, the output confirms the count:

[1] 55

Additionally, we can use our formula to compute f(P) for larger values. For instance, f(997) = f(1000) = 124,251. The verification through the R function takes a bit longer, but it provides reliable results.

Illustration of triangular triple calculations

Despite GPT-4's attempts to elaborate on the Triangle Inequality Theorem, its answers varied significantly, highlighting the importance of true comprehension in mathematics.

What are your thoughts on this problem? I welcome your comments.

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